LinkedIn Tango puzzle #742 for October 19, 2026: spoiler-free hints first, then the complete solution when you want it.
This is an earlier Tango puzzle. Latest Tango Answer: #766 (Nov 12)
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Reveal hints one at a time to avoid spoilers.
Reveal Hint #1Hint #1
Row 4 already has three moons, at columns 1, 2 and 5. Its other three cells must all be suns.
Reveal Hint #2Hint #2
Row 5 also already has three moons, so R5C3 and R5C6 must be suns. Compare columns 1 and 5 next.
Reveal Hint #3Hint #3
The consecutive moons in rows 4–5 force suns above and below them in columns 1 and 5. Complete the top rows using the equality and opposite markers.
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Tango #742 Solution
Row 1: Sun Moon Moon Sun Sun Moon. Row 2: Moon Moon Sun Sun Moon Sun. Row 3: Sun Sun Moon Moon Sun Moon. Row 4: Moon Moon Sun Sun Moon Sun. Row 5: Moon Sun Sun Moon Moon Sun. Row 6: Sun Sun Moon Moon Sun Moon.
How to Solve Tango #742
S = sun; M = moon. Start by filling the remaining spaces in row 4 with suns, because that row already has three moons. Apply the same count to row 5.
- Row 1: S M M S S M.
- Row 2: M M S S M S.
- Row 3: S S M M S M.
- Row 4: M M S S M S.
- Row 5: M S S M M S.
- Row 6: S S M M S M.
The equality markers connect suns at R1C4–R1C5, R1C4–R2C4 and R2C3–R2C4. The opposite marker joins a sun at R2C3 to a moon at R3C3. Every row and column has three suns and three moons, with no three identical symbols consecutively. All eight original symbols and four relationship markers are satisfied.
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